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Question Number 146840 by bramlexs22 last updated on 16/Jul/21

Answered by nimnim last updated on 16/Jul/21

Commented by bobhans last updated on 16/Jul/21

$$\mathrm{what}\mathrm{your}\mathrm{answer}$$

Commented by nimnim last updated on 16/Jul/21

$$Igot(8\sqrt{3}+8)r^2.butcouldnotloadthesolution!<$$

Answered by EDWIN88 last updated on 16/Jul/21

$$\left(1\right)\mathrm{TS}=4\mathrm{r}$$$$\left(2\right)\mathrm{UT}=2\mathrm{r}+2\sqrt{{\left(2\mathrm{r}\right)}^2-{\mathrm{r}}^2}=2\mathrm{r}+2\mathrm{r}\sqrt{3}$$$$\mathrm{the}\mathrm{area}\mathrm{RSTU}=\mathrm{TS}\times \mathrm{UT}$$$$=4\mathrm{r}\times (2\mathrm{r}+2\mathrm{r}\sqrt{3})$$$$={8\mathrm{r}}^2(1+\sqrt{3})$$

Commented by Rasheed.Sindhi last updated on 16/Jul/21

$$\mathcal{T}heprocessofcalculating\mathrm{UT}is$$$$mainpartofthesolution,which$$$$youhavehidden!!!Solutionisnot$$$$muchbeneficiary.$$

Commented by EDWIN88 last updated on 16/Jul/21

$$\mathrm{why}?\mathrm{what}\mathrm{your}\mathrm{working}?$$

Commented by Rasheed.Sindhi last updated on 17/Jul/21

$$Imeansomedetailoffinding$$$$lengthoftherectangle.$$

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