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Question Number 52893 by dwdkswd last updated on 14/Jan/19

$$\int \sin x\times \cos xdx$$

Answered by MJS last updated on 14/Jan/19

$$\int \sin x\cos xdx=\frac{1}{2}\int \sin 2xdx=-\frac{1}{4}\cos 2x+C=$$$$=\frac{1}{4}-\frac{1}{2}{\cos }^{2}x+C=-\frac{1}{2}{\cos }^{2}x+C$$

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