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Question Number 146911 by EDWIN88 last updated on 16/Jul/21 | ||
$$\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{2cos}\:^{\mathrm{2}} \mathrm{x}−\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}+\mathrm{y}^{\mathrm{2}} }{\mathrm{2cos}\:\mathrm{x}} \\ $$ $$\:\:\:\mathrm{y}\left(\mathrm{0}\right)=−\mathrm{1}\:\&\:\mathrm{y}\left(\mathrm{1}\right)=\mathrm{sin}\:\mathrm{x}\: \\ $$ | ||