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Question Number 146913 by mathdanisur last updated on 16/Jul/21

$$ax=by=cz=\frac{2}{3}andab+bc+ac=36abc$$$$findx+y+z=?$$

Answered by liberty last updated on 16/Jul/21

$$\{\begin{array}{l}ax=\frac{2}{3}\\ by=\frac{2}{3}\\ cz=\frac{2}{3}\end{array}$$$$\Rightarrow x+y+z=\frac{2}{3}(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})$$$$=\frac{2}{3}\left(\frac{ab+ac+bc}{abc}\right)$$$$=\frac{2}{3}\left(\frac{36abc}{abc}\right)=24$$$$$$

Commented by mathdanisur last updated on 16/Jul/21

$$thankyouSer$$

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