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Question Number 147108 by alcohol last updated on 18/Jul/21

Answered by som(math1967) last updated on 18/Jul/21

$$a)p^2$$

Answered by gsk2684 last updated on 18/Jul/21

$$lx+my+n=0touches\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$$$$\Rightarrow n^2=a^2{l}^2-b^2{m}^2$$$$\Rightarrow {(-p)}^2=a^2\cos {}^2\alpha -b^2\sin {}^2\alpha$$$$\Rightarrow p^2=a^2\cos {}^2\alpha -b^2\sin {}^2\alpha$$

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