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Question Number 147118 by bramlexs22 last updated on 18/Jul/21

Answered by Olaf_Thorendsen last updated on 20/Jul/21

As the slope is 45° the cylinder can be  developped as a square.  The walk is the diagonal of the square.  l = (√2)h = 9(√2)

$$\mathrm{As}\:\mathrm{the}\:\mathrm{slope}\:\mathrm{is}\:\mathrm{45}°\:\mathrm{the}\:\mathrm{cylinder}\:\mathrm{can}\:\mathrm{be} \\ $$$$\mathrm{developped}\:\mathrm{as}\:\mathrm{a}\:\mathrm{square}. \\ $$$$\mathrm{The}\:\mathrm{walk}\:\mathrm{is}\:\mathrm{the}\:\mathrm{diagonal}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}. \\ $$$${l}\:=\:\sqrt{\mathrm{2}}{h}\:=\:\mathrm{9}\sqrt{\mathrm{2}} \\ $$

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