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Question Number 147134 by mathdanisur last updated on 18/Jul/21

(√(2sin(x)−1)) ∙ sin(x) > 0

2sin(x)1sin(x)>0

Commented byhknkrc46 last updated on 18/Jul/21

▶ 2sin x − 1 > 0  ∧ sin x > 0  ⇒ sin x > (1/2) ∧ sin x > 0 ≡ sin x > (1/2)  ▶ (𝛑/6) < x < ((5𝛑)/6)

2sinx1>0sinx>0 sinx>12sinx>0sinx>12 π6<x<5π6

Commented bymathdanisur last updated on 18/Jul/21

thanks Sir

thanksSir

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