Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 147611 by mathdanisur last updated on 22/Jul/21

$${\left(111\right)}_{10}={\left(x\right)}_5$$$$\Rightarrow x=?$$

Answered by bobhans last updated on 22/Jul/21

$${\left(111\right)}_{10}=1\times {10}^2+1\times {10}^1+1\times {10}^0=111$$$$\Rightarrow 111={\left(421\right)}_5=4\times 5^2+2\times 5^1+1\times 5^0$$$$=100+10+1={111}_5$$

Commented by mathdanisur last updated on 22/Jul/21

$$ThankyouSir,answer421.?$$

Commented by bobhans last updated on 22/Jul/21

$$\mathrm{yes}$$

Commented by mathdanisur last updated on 22/Jul/21

$$thanksSir$$

Answered by gsk2684 last updated on 22/Jul/21

$$5\mid 111$$$$5\mid 22\to 1$$$$4\to 2$$$${\left(111\right)}_{10}={\left(421\right)}_5$$

Commented by mathdanisur last updated on 22/Jul/21

$$thankyouSir$$

Answered by Rasheed.Sindhi last updated on 22/Jul/21

$${111}_{10}=100+10+1$$$$=4\times 25+2\times 5+1$$$$=4\times 5^2+2\times 5^1+1$$$$={421}_5$$

Commented by mathdanisur last updated on 22/Jul/21

$$ThankyouSir$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com