Find a point on the curve y=(√x) where the tangent makes an angle 45° with the positive x-axis


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Question Number 147713 by Odhiambojr last updated on 22/Jul/21

$F i n d a p o i n t o n t h e c u r v e y = \sqrt{x}$ $w h e r e t h e t a n g e n t m a k e s a n a n g l e$ $45 ° w i t h t h e p o s i t i v e x - a x i s$
	Answered by Olaf_Thorendsen last updated on 22/Jul/21

	$\frac{d y}{d x} = \tan (θ (x)) = \frac{1}{2 \sqrt{x}}$ $If θ (x) = 45 °, \frac{1}{2 \sqrt{x}} = 1 \Rightarrow x = \frac{1}{4}$
	Commented by Odhiambojr last updated on 22/Jul/21

	$t h a k s M r .$
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