Find a point on the curve y=x^2 −2x−3 at which the tangent is parallel to the x-axis


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Question Number 147753 by Odhiambojr last updated on 23/Jul/21

$F i n d a p o i n t o n t h e c u r v e$ $y = x^{2} - 2 x - 3 a t w h i c h t h e t a n g e n t i s$ $p a r a l l e l t o t h e x - a x i s$
	Answered by Olaf_Thorendsen last updated on 23/Jul/21

	$\frac{d y}{d x} = 2 x - 2 = 2 (x - 1)$ $\frac{d y}{d x} = 0 \Leftrightarrow x = 1 and then y = - 4$
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