Question Number 147842 by mathdanisur last updated on 23/Jul/21
$${x}\:;\:{y}\:;\:{z}\:>\:\mathrm{0} \\ $$ $$\begin{cases}{{x}+{y}^{\mathrm{2}} +{z}^{\mathrm{3}} \:=\:\mathrm{3}}\\{{y}+{z}^{\mathrm{2}} +{x}^{\mathrm{3}} \:=\:\mathrm{3}}\\{{z}+{x}^{\mathrm{2}} +{y}^{\mathrm{3}} \:=\:\mathrm{3}}\end{cases}\:\:\Rightarrow\:\:{x}\:;\:{y}\:;\:{z}\:=\:? \\ $$
Commented bymr W last updated on 23/Jul/21
$${x}={y}={z}=\mathrm{1} \\ $$
Commented bymathdanisur last updated on 23/Jul/21
$${Thank}\:{you}\:{Sir},\:{solution} \\ $$