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Question Number 147842 by mathdanisur last updated on 23/Jul/21
x;y;z>0 {x+y2+z3=3y+z2+x3=3z+x2+y3=3⇒x;y;z=?
Commented bymr W last updated on 23/Jul/21
x=y=z=1
Commented bymathdanisur last updated on 23/Jul/21
ThankyouSir,solution
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