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Question Number 147933 by mathdanisur last updated on 24/Jul/21
Simplify(1+1cos2x)⋅(1+1cos4x)⋅(1+1cos8x)=?
Answered by som(math1967) last updated on 24/Jul/21
tanxtanx(1+1+tan2x1−tan2x)(1+1+tan22x1−tan22x)×(1+1+tan24x1−tan24x)=1tanx(2tanx1−tan2x)(21−tan22x)(21−tan24x)=1tanx×2tan2x1−tan22x×21−tan24x=1tanx×2tan4x1−tan24x=tan8xtanx[∵tan2x=2tanx1−tan2x]
Commented by mathdanisur last updated on 24/Jul/21
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