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Question Number 148334 by Sravanth last updated on 27/Jul/21

Answered by Rasheed.Sindhi last updated on 27/Jul/21

$$3^6\times \left(2^{-2}\times 3^{5\times -2}\right)\times {\left(2\times 3^2\right)}^2$$$$3^6\times 2^{-2}\times 3^{-10}\times 2^2\times 3^4$$$$3^6\times 3^{-10}\times 3^4\times 2^{-2}\times 2^2$$$$3^{6-10+4}\times 2^{-2+2}$$$$3^0\times 2^0=1\times 1=1$$

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