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Question Number 148350 by Fikret last updated on 27/Jul/21

(((1/2)+(1/3)+....+(1/9))/((9/1)+(8/2)+...+(1/9)))=?

$$\frac{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+....+\frac{\mathrm{1}}{\mathrm{9}}}{\frac{\mathrm{9}}{\mathrm{1}}+\frac{\mathrm{8}}{\mathrm{2}}+...+\frac{\mathrm{1}}{\mathrm{9}}}=? \\ $$

Commented by liberty last updated on 27/Jul/21

= ((4609)/(48610))

$$=\:\frac{\mathrm{4609}}{\mathrm{48610}} \\ $$

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