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Question Number 148453 by mathdanisur last updated on 28/Jul/21

$$\frac{(n+1)!}{n!}=38\Rightarrow n=?$$

Answered by puissant last updated on 28/Jul/21

$$\Rightarrow \frac{(\mathrm{n}+1)\times \mathrm{n}!}{\mathrm{n}!}=38$$$$\Rightarrow \mathrm{n}+1=38$$$$\Rightarrow \mathrm{n}=37..$$

Commented by mathdanisur last updated on 28/Jul/21

$$ThankyouSer$$

Answered by Olaf_Thorendsen last updated on 28/Jul/21

$$\frac{(n+1)!}{n!}=38=\frac{(n+1)n!}{n!}=n+1$$$$\Rightarrow n=37$$

Commented by mathdanisur last updated on 28/Jul/21

$$ThankyouSer$$

Answered by Rasheed.Sindhi last updated on 28/Jul/21

$$\frac{(n+1)!}{n!}=38\Rightarrow n=?$$$$\frac{(n+1)!}{n!(n+1)}=\frac{38}{n+1}$$$$\frac{(n+1)!}{(n+1)!}=\frac{38}{n+1}$$$$1=\frac{38}{n+1}$$$$n+1=38$$$$n=38-1=37$$

Commented by mathdanisur last updated on 28/Jul/21

$$ThankyouSer$$

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