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Question Number 148515 by mathdanisur last updated on 28/Jul/21

$F i n d t h e s u m o f t h e r o o t s o f t h e e q u a t i o n :$ $x^{2} - 2 x - 3 ∣ x - 1 ∣ + 3 = 0$
	Answered by dumitrel last updated on 28/Jul/21
	$∣x−1∣^2 −3∣x−1∣+2=0⇒∣x−1∣∈{1,2} x−1∈{±1;±2}⇒sum=4$
	$∣ x - 1 ∣^{2} - 3 ∣ x - 1 ∣ + 2 = 0 \Rightarrow∣ x - 1 ∣\in {1, 2}$ $x - 1 \in {\pm 1; \pm 2} \Rightarrow s u m = 4$
	Commented by mathdanisur last updated on 28/Jul/21

	$T h a n k y o u S e r c o o l$
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