A(0;0) ; B(−2;4) and C(−6;14) if the triangle has vertices, find the lenght of the median drawn from the vertx C


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Question Number 148550 by mathdanisur last updated on 29/Jul/21

$A (0; 0); B (- 2; 4) a n d C (- 6; 14)$ $i f t h e t r i a n g l e h a s v e r t i c e s, f i n d t h e$ $l e n g h t o f t h e m e d i a n d r a w n f r o m$ $t h e v e r t x C$
Commented by MJS_new last updated on 29/Jul/21

$first show us a triangle which has n o vertices$
Commented by Ar Brandon last updated on 29/Jul/21
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	Answered by Rasheed.Sindhi last updated on 29/Jul/21

	$M i d p o i n t o f A B = M = (\frac{- 2 + 0}{2}, \frac{4 + 0}{2}) = (- 1, 2)$ $T h e m e d i a n t h r o u g h C$ $C M = \sqrt{{(- 6 - (- 1))}^{2} + (14 - 2)}$ $= \sqrt{25 + 144} = \sqrt{169} = 13$
	Commented by mathdanisur last updated on 29/Jul/21

	$T h a n k y o u S e r, c o o l$
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