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Question Number 148600 by EDWIN88 last updated on 29/Jul/21

$$\underset{x\to -\mathrm{\infty }}{\lim }\sqrt[3]{27x^3-3x^2}+\sqrt[3]{8x^3-x^2}-\sqrt[3]{x^3-4x^2+2021}=?$$

Answered by bemath last updated on 29/Jul/21

$$\underset{x\to -\mathrm{\infty }}{\lim }-\sqrt[3]{27}(\mathrm{x}-\frac{3}{3\times 27})-\sqrt[3]{8}(\mathrm{x}-\frac{1}{3\times 8})+\sqrt[3]{1}(\mathrm{x}-\frac{4}{3\times 1})$$$$=\underset{x\to -\mathrm{\infty }}{\lim }(-3\mathrm{x}+\frac{1}{9})-(2\mathrm{x}-\frac{1}{12})+(\mathrm{x}-\frac{4}{3})=+\mathrm{\infty }$$

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