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Question Number 148858 by Tawa11 last updated on 31/Jul/21

Answered by EDWIN88 last updated on 01/Aug/21

Commented by EDWIN88 last updated on 01/Aug/21

$$shadedarea=2\times \frac{1}{4}\pi \left(2^2\right)+16-\frac{1}{4}\pi \left(4^2\right)+2(4-\frac{1}{4}\pi \left(2^2\right))$$$$=2\pi +16-4\pi +8-2\pi$$$$=24-4\pi$$

Commented by Tawa11 last updated on 01/Aug/21

$$\mathrm{Thanks}\mathrm{sir}.\mathrm{God}\mathrm{bless}\mathrm{you}.$$

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