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Question Number 148861 by mathdanisur last updated on 31/Jul/21

Answered by dumitrel last updated on 01/Aug/21

$${\left(2x\right)}^4+324=(4x^2-12x+18)(4x^2+12x+18)$$$$f\left(x\right)=4x^2-12x+18\Rightarrow f(x+3)=4x^2+12x+18$$$${\left(2x\right)}^4+324=f\left(x\right)\cdot f(x+3)$$$$\frac{f\left(5\right)f\left(8\right)f\left(11\right)f\left(14\right)f\left(17\right)f\left(20\right)f\left(23\right)f\left(26\right)f\left(29\right)f\left(32\right)}{f\left(2\right)f\left(5\right)f\left(8\right)f\left(11\right)f\left(14\right)f\left(17\right)f\left(20\right)f\left(23\right)f\left(26\right)f\left(29\right)}=\frac{f\left(32\right)}{f\left(2\right)}=373$$$$$$$$$$

Commented by mathdanisur last updated on 01/Aug/21

$$Cool,ThankYouSer$$

Commented by mathdanisur last updated on 01/Aug/21

$$DearSer,answer:373$$

Commented by mathdanisur last updated on 01/Aug/21

$$SorrydearSer,f\left(32\right)=?andf\left(2\right)=?$$

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