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Question Number 148880 by DELETED last updated on 01/Aug/21

Answered by DELETED last updated on 01/Aug/21

$$\mid \mathrm{AC}\mid =\sqrt{{10}^2+{10}^2}=10\sqrt{2}\mathrm{cm}$$$$\mid \mathrm{CG}\mid =10\mathrm{cm}$$$$\to \mathrm{Luas}\mathrm{\Delta }\mathrm{ACG}:$$$$=\frac{10\times 10\sqrt{2}}{2}=50\sqrt{2}{\mathrm{cm}}^2$$

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