Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 148881 by DELETED last updated on 01/Aug/21

Answered by Rasheed.Sindhi last updated on 01/Aug/21

$$▴ABC=\sqrt{\mathrm{s}(\mathrm{s}-\mathrm{a})(\mathrm{s}-\mathrm{b})(\mathrm{s}-\mathrm{c})}$$$$\mathrm{s}=\frac{\mathrm{a}+\mathrm{b}+\mathrm{c}}{2}=\frac{7+6+8}{2}=10.5$$$$▴ABC=\sqrt{10.5(10.5-6)(10.5-8)(10.5-7)}$$$$=\sqrt{10.5\times 4.5\times 2.5\times 3.5}\approx 20.33{\mathrm{cm}}^2$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com