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Question Number 148884 by 0731619 last updated on 01/Aug/21
Answered by aleks041103 last updated on 03/Aug/21
∫0∞dxa+x13=1a∫0∞dx1+(xa1/13)13==a1/13a∫0∞d(x/a1/13)1+(x/a1/13)13ifa>0,thenwesubstituteu=x/a1/13Then:∫0∞dxa+x13=a−12/13∫0∞dx1+x13⇒∫0∞dx1+x13∫0∞dx13+x13=1312/13
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