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Question Number 148886 by DELETED last updated on 01/Aug/21

Answered by Rasheed.Sindhi last updated on 01/Aug/21

$$\frac{AC}{\sin B}=\frac{BC}{\sin A}$$$$\frac{8}{\sin 60}=\frac{6}{\sin \theta }$$$$\frac{8}{\frac{\sqrt{3}}{2}}=\frac{6}{\sin \theta }$$$$\frac{6}{\sin \theta }=\frac{16}{\sqrt{3}}$$$$\sin \theta =\frac{\sqrt{3}}{16}\times 6=\frac{3\sqrt{3}}{8}$$$$\theta ={\sin }^{-1}\left(\frac{3\sqrt{3}}{8}\right)\approx 40.5°$$

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