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Question Number 148905 by DELETED last updated on 01/Aug/21

	Answered by DELETED last updated on 01/Aug/21
	$Answered: −∫_2 ^4 (x^2 −5x )dx=− [(1/3)x^3 −(5/2)x^2 ] _2 ^4 = −[{((64)/3) − ((80)/2) }−{(8/3) − ((20)/2)} ] =−((56)/3) +((90)/3) = ((34)/3) = 11,33 unit^2 //$
	$Answered :$ $- \underset{2}{\int^{4}} (x^{2} - 5 x) dx = - [\frac{1}{3} x^{3} - \frac{5}{2} x^{2}] \underset{2}{\overset{4}{}}$ $= - [{\frac{64}{3} - \frac{80}{2}} - {\frac{8}{3} - \frac{20}{2}}]$ $= - \frac{56}{3} + \frac{90}{3} = \frac{34}{3} = 11, 33 {unit}^{2} / /$
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