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Question Number 148914 by naka3546 last updated on 01/Aug/21

$$Solvetheequation$$$$2^x+x=11$$$$withOmegaFunction.$$

Commented by naka3546 last updated on 01/Aug/21

$$thankyou,sir.$$

Commented by mr W last updated on 01/Aug/21

$$2^{11}=(11-x)2^{11-x}$$$$2^{11}\ln 2=(11-x)\ln 2e^{(11-x)\ln 2}$$$$(11-x)\ln 2=W\left(2^{11}\ln 2\right)$$$$x=11-\frac{W\left(2^{11}\ln 2\right)}{\ln 2}=3$$

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