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Question Number 148917 by DELETED last updated on 01/Aug/21

Answered by DELETED last updated on 01/Aug/21

$${\mathrm{R}}_{\mathrm{s}2}=16+4+5=25\mathrm{\Omega }$$$${\mathrm{i}}_{\mathrm{total}}=\frac{\mathrm{V}}{{\mathrm{R}}_{\mathrm{s}2}}=\frac{12.5}{25}=0.5\mathrm{A}$$$${\mathrm{i}}_{\mathrm{total}}={\mathrm{i}}_{\mathrm{p}}=0.5\mathrm{A}$$$${\mathrm{V}}_{\mathrm{p}}={\mathrm{i}}_{\mathrm{p}}\times {\mathrm{R}}_{\mathrm{p}}=0.5\times 4=2\mathrm{vol}$$$$$$

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