(B^3 −2B^2 −4B+8)y=0 solve the differencial equation


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Question Number 148939 by Rankut last updated on 01/Aug/21

$(B^{3} - 2 B^{2} - 4 B + 8) y = 0$ $s o l v e t h e d i f f e r e n c i a l e q u a t i o n$
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