let f:R→R be a continuius function such that for any two real numbers x and y ∣f(x)−f(y)∣≤10∣x−y∣^(201) then prove that f(2019)+f(2022)=2 f(2021)


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Question Number 148990 by gsk2684 last updated on 02/Aug/21

$l e t f : R \to R b e a c o n t i n u i u s f u n c t i o n$ $s u c h t h a t f o r a n y t w o r e a l n u m b e r s$ $x a n d y ∣ f (x) - f (y) ∣⩽ 10 ∣ x - y ∣^{201}$ $t h e n p r o v e t h a t$ $f (2019) + f (2022) = 2 f (2021)$
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