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Question Number 149123 by Samimsultani last updated on 03/Aug/21

Answered by EDWIN88 last updated on 03/Aug/21

2^(99)

$$\mathrm{2}^{\mathrm{99}} \\ $$

Answered by abdurehime last updated on 03/Aug/21

(1/2)×2^(100)   =2^(−1) ×2^(100)   =2^(−1+100)   =2^(99)

$$\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}^{\mathrm{100}} \\ $$$$=\mathrm{2}^{−\mathrm{1}} ×\mathrm{2}^{\mathrm{100}} \\ $$$$=\mathrm{2}^{−\mathrm{1}+\mathrm{100}} \\ $$$$=\mathrm{2}^{\mathrm{99}} \\ $$$$ \\ $$

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