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Question Number 14921 by Tinkutara last updated on 05/Jun/17

A car travelling at 36 km/h due North  turns West in 5 seconds and maintains  the same speed. What is the acceleration  of the car?

$$\mathrm{A}\:\mathrm{car}\:\mathrm{travelling}\:\mathrm{at}\:\mathrm{36}\:\mathrm{km}/\mathrm{h}\:\mathrm{due}\:\mathrm{North} \\ $$$$\mathrm{turns}\:\mathrm{West}\:\mathrm{in}\:\mathrm{5}\:\mathrm{seconds}\:\mathrm{and}\:\mathrm{maintains} \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{speed}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{car}? \\ $$

Commented by ajfour last updated on 05/Jun/17

south-west (along △v^�  )

$${south}-{west}\:\left({along}\:\bigtriangleup\bar {{v}}\:\right) \\ $$

Commented by Tinkutara last updated on 05/Jun/17

Thanks Sir! My small doubt cleared.

$$\mathrm{Thanks}\:\mathrm{Sir}!\:\mathrm{My}\:\mathrm{small}\:\mathrm{doubt}\:\mathrm{cleared}. \\ $$

Answered by ajfour last updated on 05/Jun/17

∣ a^� ∣=∣((△v^� )/(△t))∣  = ((10(√2))/5)= 2(√2) m/s .

$$\mid\:\bar {\boldsymbol{{a}}}\mid=\mid\frac{\bigtriangleup\bar {\boldsymbol{{v}}}}{\bigtriangleup{t}}\mid\:\:=\:\frac{\mathrm{10}\sqrt{\mathrm{2}}}{\mathrm{5}}=\:\mathrm{2}\sqrt{\mathrm{2}}\:{m}/{s}\:. \\ $$

Commented by Tinkutara last updated on 05/Jun/17

What will be the direction of this  acceleration?

$$\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{this} \\ $$$$\mathrm{acceleration}? \\ $$

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