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Question Number 149291 by mathdanisur last updated on 04/Aug/21

$$f\left(x\right)=2{sinx}^2-{cos}^{2}x-2$$$$f{}^{{}^{\prime }}\left(x\right)=?$$

Answered by nimnim last updated on 04/Aug/21

$$f{}^{\prime }\left(x\right)=4x.{cosx}^2+2cosx.sinx-0=4x.cos\left(x^2\right)+sin\left(2x\right)$$

Answered by Ar Brandon last updated on 04/Aug/21

$$f\left(x\right)=2\sin \left(x^2\right)-{\cos }^{2}x-2$$$$f{}^{\prime }\left(x\right)=4x\cos \left(x^2\right)+2\sin x\cos x$$$$=4x\cos \left(x^2\right)+\sin 2x$$

Commented by Ar Brandon last updated on 04/Aug/21

$$\mathrm{Haha}!{\mathrm{J}}^{\prime }\mathrm{avais}\mathrm{commis}\mathrm{cette}\mathrm{m}\widehat{\mathrm{e}me}\mathrm{erreur}$$$$\mathrm{avant}\mathrm{de}{\mathrm{m}}^{\prime }\mathrm{en}\mathrm{rendre}\mathrm{compte},\mathrm{apr}\stackrel{`}{\mathrm{e}s}\mathrm{avoir}$$$$\mathrm{vu}\mathrm{les}\mathrm{diff}\acute{\mathrm{e}rentes}\mathrm{solutions}\mathrm{propos}\acute{\mathrm{e}es}.$$

Commented by Ar Brandon last updated on 04/Aug/21

😇

Commented by mathdanisur last updated on 04/Aug/21

$$ThankYouSer$$

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