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Question Number 149372 by fotosy2k last updated on 05/Aug/21

Answered by john_santu last updated on 05/Aug/21

$$\underset{x\to 0}{\lim }\frac{\sin (\mathrm{x}+2\sin \mathrm{x})}{\sin \mathrm{x}}=$$$$\underset{x\to 0}{\lim }\frac{\frac{\sin (\mathrm{x}+2\sin \mathrm{x})}{\mathrm{x}+2\sin \mathrm{x}}.\mathrm{x}+2\sin \mathrm{x}}{\frac{\sin \mathrm{x}}{\mathrm{x}}.\mathrm{x}}$$$$=\underset{x\to 0}{\lim }\frac{\mathrm{x}+2\sin \mathrm{x}}{\mathrm{x}}=1+2=3$$

Commented by fotosy2k last updated on 05/Aug/21

$$thankyou$$

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