Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 149503 by mathdanisur last updated on 05/Aug/21

$$\mathrm{Calcular}:$$$$3\sin \cdot (150-\mathit{\alpha })-2\cos \cdot (60-\mathit{\alpha })=\frac{1}{2}$$

Answered by MJS_new last updated on 05/Aug/21

$$\iff$$$$3\sin (\alpha +30)-2\sin (\alpha +30)=\frac{1}{2}$$$$\iff$$$$\sin (\alpha +30)=\frac{1}{2}$$$$\iff$$$$\alpha =360n\vee \alpha =120+360n\mathrm{\forall }n\in \mathbb{Z}$$

Commented by mathdanisur last updated on 05/Aug/21

$$\mathrm{Cool},\mathrm{thank}\mathrm{you}\mathbf{Ser}$$

Answered by Ar Brandon last updated on 05/Aug/21

$$3\sin (150°-\alpha )-2\cos (60°-\alpha )=\frac{1}{2}$$$$3\sin (90°+60°-\alpha )-2\cos (60°-\alpha )=\frac{1}{2}$$$$3\cos (60°-\alpha )-2\cos (60°-\alpha )=\frac{1}{2}$$$$\cos (60°-\alpha )=\frac{1}{2}\Rightarrow 60°-\alpha =\pm 60°+360n°$$$$\Rightarrow \alpha =60°\mp 60°-360n°,n\in \mathbb{Z}$$

Commented by mathdanisur last updated on 06/Aug/21

$$\mathrm{Thankyou}\mathbf{Ser}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com