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Question Number 149914 by 7770 last updated on 08/Aug/21

show that∫_1 ^2 (((2+6ΞΈ^2 βˆ’2𝛉^3 )/(𝛉^2 (𝛉^2 +1))))d𝛉=1.606

$$\boldsymbol{{show}}\:\boldsymbol{{that}}\int_{\mathrm{1}} ^{\mathrm{2}} \left(\frac{\mathrm{2}+\mathrm{6}\theta^{\mathrm{2}} βˆ’\mathrm{2}\boldsymbol{\theta}^{\mathrm{3}} }{\boldsymbol{\theta}^{\mathrm{2}} \left(\boldsymbol{\theta}^{\mathrm{2}} +\mathrm{1}\right)}\right)\boldsymbol{{d}\theta}=\mathrm{1}.\mathrm{606} \\ $$

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