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Question Number 150135 by Gbenga last updated on 09/Aug/21

4n^2 +2n=e^n

$$\mathrm{4}{n}^{\mathrm{2}} +\mathrm{2}{n}={e}^{{n}} \\ $$

Answered by MJS_new last updated on 10/Aug/21

you can only approximate  n≈−.684294∨n≈4.49967

$$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${n}\approx−.\mathrm{684294}\vee{n}\approx\mathrm{4}.\mathrm{49967} \\ $$

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