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Question Number 150323 by jlewis last updated on 11/Aug/21

a pmf of a random variable Xis given as  f(x)=(e^(−10) . 10^x )/x!  X=0 , 1 ,2 ... find   P(x<16)

$$\mathrm{a}\:\mathrm{pmf}\:\mathrm{of}\:\mathrm{a}\:\mathrm{random}\:\mathrm{variable}\:\mathrm{Xis}\:\mathrm{given}\:\mathrm{as} \\ $$ $$\mathrm{f}\left(\mathrm{x}\right)=\left(\mathrm{e}^{−\mathrm{10}} .\:\mathrm{10}^{\mathrm{x}} \right)/\mathrm{x}!\:\:\mathrm{X}=\mathrm{0}\:,\:\mathrm{1}\:,\mathrm{2}\:...\:\mathrm{find}\: \\ $$ $$\mathrm{P}\left(\mathrm{x}<\mathrm{16}\right) \\ $$

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