Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 150516 by mathdanisur last updated on 13/Aug/21

Compare:  x = 2^3^2^3        and     y = 3^2^3^2

$$\mathrm{Compare}: \\ $$$$\boldsymbol{\mathrm{x}}\:=\:\mathrm{2}^{\mathrm{3}^{\mathrm{2}^{\mathrm{3}} } } \:\:\:\:\:\mathrm{and}\:\:\:\:\:\boldsymbol{\mathrm{y}}\:=\:\mathrm{3}^{\mathrm{2}^{\mathrm{3}^{\mathrm{2}} } } \\ $$

Commented by mr W last updated on 13/Aug/21

x=2^3^8  =8^3^7  , y=3^2^9    3^7 =3×3^3 ×3^3 =3×81×81>3×600>1000  2^9 <(2^(10) /2)=((1024)/2)=512<1000  ⇒3^7 >2^9   ⇒8^3^7  >3^2^9    ⇒x>y

$${x}=\mathrm{2}^{\mathrm{3}^{\mathrm{8}} } =\mathrm{8}^{\mathrm{3}^{\mathrm{7}} } ,\:{y}=\mathrm{3}^{\mathrm{2}^{\mathrm{9}} } \\ $$$$\mathrm{3}^{\mathrm{7}} =\mathrm{3}×\mathrm{3}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{3}} =\mathrm{3}×\mathrm{81}×\mathrm{81}>\mathrm{3}×\mathrm{600}>\mathrm{1000} \\ $$$$\mathrm{2}^{\mathrm{9}} <\frac{\mathrm{2}^{\mathrm{10}} }{\mathrm{2}}=\frac{\mathrm{1024}}{\mathrm{2}}=\mathrm{512}<\mathrm{1000} \\ $$$$\Rightarrow\mathrm{3}^{\mathrm{7}} >\mathrm{2}^{\mathrm{9}} \\ $$$$\Rightarrow\mathrm{8}^{\mathrm{3}^{\mathrm{7}} } >\mathrm{3}^{\mathrm{2}^{\mathrm{9}} } \\ $$$$\Rightarrow{x}>{y} \\ $$

Commented by mathdanisur last updated on 13/Aug/21

Thank you Ser

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{Ser} \\ $$

Answered by MJS_new last updated on 13/Aug/21

x=2^(6561)   y=3^(512)   x>y

$${x}=\mathrm{2}^{\mathrm{6561}} \\ $$$${y}=\mathrm{3}^{\mathrm{512}} \\ $$$${x}>{y} \\ $$

Commented by mathdanisur last updated on 13/Aug/21

Thank you Ser

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{Ser} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com