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Question Number 174440 by mathlove last updated on 01/Aug/22

$$1+\sqrt{3^x}=2^{x}x=?$$

Commented by infinityaction last updated on 01/Aug/22

$$2$$

Commented by mathlove last updated on 01/Aug/22

$$solution??$$

Commented by MJS_new last updated on 02/Aug/22

$$\mathrm{no}\mathrm{general}\mathrm{solution}\mathrm{method}.\mathrm{in}\mathrm{this}\mathrm{case}\mathrm{use}$$$$\mathrm{your}\mathrm{experience}.3^2=9;\sqrt{9}=3;3+1=4=2^2$$$$\mathrm{but}\mathrm{here}\mathrm{you}\mathrm{have}\mathrm{to}\mathrm{approximate}:1+\sqrt{5^x}=3^x$$

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