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Question Number 150960 by john_santu last updated on 17/Aug/21

given x ,y is a prime number   with x<y and x^3 +y^3 +20l8 =30y^2 −300y+30l8  find the value of x

$$\mathrm{given}\:\mathrm{x}\:,\mathrm{y}\:\mathrm{is}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}\: \\ $$ $$\mathrm{with}\:\mathrm{x}<\mathrm{y}\:\mathrm{and}\:\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} +\mathrm{20l8}\:=\mathrm{30y}^{\mathrm{2}} −\mathrm{300y}+\mathrm{30l8} \\ $$ $$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$

Commented byotchereabdullai@gmail.com last updated on 22/Aug/21

nice

$$\mathrm{nice} \\ $$

Answered by EDWIN88 last updated on 17/Aug/21

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