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Question Number 150968 by mathdanisur last updated on 17/Aug/21

Answered by dumitrel last updated on 17/Aug/21

Σ(((2x+y)(3x^2 +xy+2y^2 ))/(2x^2 +y^2 ))≤Σ3(x+y)=6(x+y+z)

$$\Sigma\frac{\left(\mathrm{2}{x}+{y}\right)\left(\mathrm{3}{x}^{\mathrm{2}} +{xy}+\mathrm{2}{y}^{\mathrm{2}} \right)}{\mathrm{2}{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\leqslant\Sigma\mathrm{3}\left({x}+{y}\right)=\mathrm{6}\left({x}+{y}+{z}\right) \\ $$

Commented by mathdanisur last updated on 17/Aug/21

nice Ser thank you

$$\mathrm{nice}\:\mathrm{Ser}\:\mathrm{thank}\:\mathrm{you} \\ $$

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