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Question Number 151073 by mathdanisur last updated on 18/Aug/21

the value of   (((50)),(0) )^2 + (((50)),(1) )^2 + (((50)),(2) )^2 +...+ (((50)),((49)) )^2 + (((50)),((50)) )^2

thevalueof(500)2+(501)2+(502)2+...+(5049)2+(5050)2

Answered by ArielVyny last updated on 18/Aug/21

S_n =Σ_(k=0) ^(50) (C_(50) ^k )^2   ln(S_n )=2Σ_(k=0) ^(50) ln(((50!)/(k!(50−k)!)))=2ln(50!)(50+1)−2Σ_(k=0) ^(50) ln[k!(50−k)!]  ln(S_n )=102ln(50!)−2Σ_(k=0) ^(50) ln(k!)−2Σ_(k=0) ^(50) ln(50−k)!    ln(S_n )=102ln(50!)→S_n =e^(102ln(50!)) =e^(ln(50!)^(102) )   S_n =(50!)^(102)

Sn=50k=0(C50k)2ln(Sn)=250k=0ln(50!k!(50k)!)=2ln(50!)(50+1)250k=0ln[k!(50k)!]ln(Sn)=102ln(50!)250k=0ln(k!)250k=0ln(50k)!ln(Sn)=102ln(50!)Sn=e102ln(50!)=eln(50!)102Sn=(50!)102

Commented by mathdanisur last updated on 18/Aug/21

Thank you Ser, answer:  (((100)),((50)) )

ThankyouSer,answer:(10050)

Commented by mr W last updated on 18/Aug/21

wrong!  S=a+b  ln S=ln (a+b)≠ln a+ln b

wrong!S=a+blnS=ln(a+b)lna+lnb

Answered by mr W last updated on 18/Aug/21

in (1+x)^n (1+x)^n   the coef. of x^n  is Σ_(k=0) ^n C_k ^n C_(n−k) ^n =Σ_(k=0) ^n (C_k ^n )^2   but (1+x)^n (1+x)^n =(1+x)^(2n)  and the  the coef. of x^n  is C_n ^(2n) . therefore  Σ_(k=0) ^n (C_k ^n )^2 =C_n ^(2n)   ⇒(C_0 ^(50) )^2 +(C_1 ^(50) )^2 +...+(C_(50) ^(50) )^2 =C_(50) ^(100)

in(1+x)n(1+x)nthecoef.ofxnisnk=0CknCnkn=nk=0(Ckn)2but(1+x)n(1+x)n=(1+x)2nandthethecoef.ofxnisCn2n.thereforenk=0(Ckn)2=Cn2n(C050)2+(C150)2+...+(C5050)2=C50100

Commented by mathdanisur last updated on 18/Aug/21

Thank you Ser

ThankyouSer

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