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Question Number 151435 by mathdanisur last updated on 21/Aug/21

Commented by peter frank last updated on 21/Aug/21

$$\mathrm{new}\mathrm{ID}\mathrm{but}\mathrm{same}\mathrm{guy}.\mathrm{mr}\mathrm{w}\mathrm{do}\mathrm{you}\mathrm{remember}?$$

Commented by mr W last updated on 21/Aug/21

$$eventhesameID?$$

Commented by peter frank last updated on 21/Aug/21

$$\mathrm{different}\mathrm{ID}$$

Commented by Rasheed.Sindhi last updated on 24/Aug/21

$$Sameorsimilar$$

Answered by mr W last updated on 21/Aug/21

$$\sin x\frac{\sin 37\sin 16}{\sin 32\sin 7}=\sin 88\cos x-\cos 88\sin x$$$$\sin x(\frac{\sin 37\sin 16}{\sin 32\sin 7}+\cos 88)=\sin 88\cos x$$$$\tan x=\frac{\sin 88}{\frac{\sin 37\sin 16}{\sin 32\sin 7}+\cos 88}$$$$x=k\pi +{\tan }^{-1}\frac{\sin 88}{\frac{\sin 37\sin 16}{\sin 32\sin 7}+\cos 88}$$

Commented by mathdanisur last updated on 21/Aug/21

$$\mathrm{Thank}\mathrm{You}\mathbf{S}\mathrm{er}$$

Commented by MJS_new last updated on 21/Aug/21

$$x=21°\vee x=-159°\mathrm{for}-180°⩽x<180°$$

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