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Question Number 151602 by DELETED last updated on 22/Aug/21

Answered by DELETED last updated on 22/Aug/21

$$1.\mathrm{g}).\mathrm{Letak}\mathrm{persentil}\mathrm{ke}-65$$$${\mathrm{P}}_{\mathrm{i}}=\frac{\mathrm{i}(\mathrm{N}+1)}{100}\to {\mathrm{P}}_{65}=\frac{65(25+1)}{100}$$$$=\frac{65\times 26}{100}=16,9$$$$\mathrm{Nilai}\mathrm{persentil}\mathrm{ke}65={\mathrm{x}}_{16}+0,9({\mathrm{x}}_{17}-{\mathrm{x}}_{16})$$$$=19+0,9=19,9$$

Answered by DELETED last updated on 22/Aug/21

$$1.\mathrm{a}).\stackrel{-}{\mathrm{x}}=\frac{\mathrm{\Sigma }{\mathrm{x}}_{\mathrm{i}}}{\mathrm{N}}=\frac{91+93+85+86+95}{25}$$$$=\frac{184+171+95}{25}=\frac{355+95}{25}=\frac{450}{25}=18$$$$\mathrm{b}).\mathrm{median}=\mathrm{nilai}\mathrm{data}\mathrm{yg}\mathrm{ke}-13$$$$\mathrm{diurutkan}\mathrm{dari}\mathrm{yg}\mathrm{terkecil}$$$$12,13,13,14,14,15,16,16,16,$$$$17,17,18,18,18,...$$$$\mathrm{jadi}\mathrm{nilai}\mathrm{median}=18$$

Answered by DELETED last updated on 22/Aug/21

$$1.\mathrm{c}).12,13,13,14,14,15,16,16,16,$$$$17,17,18,18,18,19,19,20,$$$$20,20,20,22,22,23,23,25$$$$\mathrm{nilai}\mathrm{modus}\mathrm{adalah}\mathrm{nilai}$$$$\mathrm{yg}\mathrm{paling}\mathrm{banyak}\mathrm{yaitu}=20//$$$$1.\mathrm{d}).\mathrm{Kuartil}1=\frac{{\mathrm{x}}_6+{\mathrm{x}}_7}{2}=\frac{15+16}{2}=15,5//$$$$1.\mathrm{e}).\mathrm{kuartil}3=\frac{{\mathrm{x}}_{19}+{\mathrm{x}}_{20}}{2}=\frac{20+20}{2}=20//$$

Answered by DELETED last updated on 22/Aug/21

$$\mathrm{langkah}\mathrm{cari}\mathrm{kuartil}\mathrm{pakai}\mathrm{rumus}$$$$\bullet \mathrm{Letak}\mathrm{kuartil}\mathrm{ke}-\mathrm{i}=\frac{\mathrm{i}(\mathrm{N}+1)}{10}$$$$\mathrm{letak}{\mathrm{Q}}_1=\frac{1(25+1)}{4}=\frac{26}{4}=6,5$$$$\mathrm{nilai}{\mathrm{Q}}_1={\mathrm{x}}_6+0,5({\mathrm{x}}_7-{\mathrm{x}}_6)$$$$=15+0,5(16-15)=15+0,5=15,5$$

Answered by DELETED last updated on 22/Aug/21

$$\mathrm{Jawab}\mathrm{no}2$$$$\mathrm{a}).\stackrel{-}{\mathrm{x}}=\frac{\mathrm{\Sigma }{\mathrm{x}}_{\mathrm{i}}.{\mathrm{f}}_{\mathrm{i}}}{\mathrm{\Sigma }{\mathrm{f}}_{\mathrm{i}}}$$$$=\frac{43\times 4+44\times 6+45\times 4+46\times 8+47\times 3+48\times 4}{4+6+4+8+3+4}$$$$=\frac{172+264+180+368+141+192}{29}$$$$=\frac{1317}{29}=45,41//$$$$$$

Answered by DELETED last updated on 22/Aug/21

$$\mathrm{Letak}\mathrm{median}=\frac{2(\mathrm{N}+1)}{4}$$$$=\frac{2(29+1)}{4}=\frac{30}{2}=15$$$$\mathrm{jadi}\mathrm{median}={\mathrm{x}}_{15}=45//$$$$$$$$$$

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