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Question Number 151677 by Tawa11 last updated on 22/Aug/21

Answered by Olaf_Thorendsen last updated on 22/Aug/21

$$\mathrm{R}=1\mathrm{\Omega }+\frac{1}{\frac{1}{3\mathrm{\Omega }+3\mathrm{\Omega }}+\frac{1}{3\mathrm{\Omega }+3\mathrm{\Omega }}}$$$$\mathrm{R}=1\mathrm{\Omega }+\frac{1}{\frac{1}{6\mathrm{\Omega }}+\frac{1}{6\mathrm{\Omega }}}$$$$\mathrm{R}=1\mathrm{\Omega }+3\mathrm{\Omega }=4\mathrm{\Omega }$$$$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{12\mathrm{V}}{4\mathrm{\Omega }}=3\mathrm{A}$$

Commented by Tawa11 last updated on 22/Aug/21

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}.$$

Commented by Olaf_Thorendsen last updated on 22/Aug/21

$${\mathrm{It}}^{\prime }\mathrm{s}\mathrm{funny}\mathrm{because}\mathrm{we}\mathrm{have}\mathrm{a}$$$$\mathrm{resistance}\mathrm{of}3\mathrm{\Omega }\mathrm{by}\mathrm{using}\mathrm{four}$$$$\mathrm{resistances}\mathrm{of}3\mathrm{\Omega }.$$$$\mathrm{In}\mathrm{the}\mathrm{real}\mathrm{life},\mathrm{only}\mathrm{one}\mathrm{resistance}$$$$\mathrm{of}3\mathrm{\Omega }\mathrm{is}\mathrm{enough}\mathrm{to}\mathrm{obtain}3\mathrm{\Omega }.$$

Commented by Tawa11 last updated on 22/Aug/21

$$\mathrm{Ohh}.\mathrm{Thanks}\mathrm{sir}.\mathrm{I}\mathrm{understand}\mathrm{better}.$$

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