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Question Number 151766 by mathdanisur last updated on 22/Aug/21

Commented by tabata last updated on 23/Aug/21

ln(y) ln(x)=ln(3)⇒ln(y)=((ln(3))/(ln(x))) ⇒(y^′ /y)=−((ln(3))/(x (ln(x))^2 )) (dy/dx) ∣y=e ⇒(dy/dx) = − ((e ln (3))/(x (ln(x))^2 )) = − ((ln(3)^e )/(x (ln(x))^2 )) ⟨M.T ⟩

ln(y)ln(x)=ln(3)⇒ln(y)=ln(3)ln(x)⇒y′y=−ln(3)x(ln(x))2dydx∣y=e⇒dydx=−eln(3)x(ln(x))2=−ln(3)ex(ln(x))2⟨M.T⟩

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