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Question Number 151790 by mathdanisur last updated on 23/Aug/21

Answered by Olaf_Thorendsen last updated on 24/Aug/21

$$u_1=\sqrt{99}$$$$u_n=\sqrt{102-3n+u_{n-1}}$$$$u_{33}=\sqrt{3+\sqrt{6+\sqrt{9+...+\sqrt{96+\sqrt{99}}}}}$$$$u_{33}\approx 2,469925717$$

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