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Question Number 151832 by DELETED last updated on 23/Aug/21

Answered by DELETED last updated on 23/Aug/21

$$57).{\mathrm{R}}_{\mathrm{s}}=2\mathrm{R}+2\mathrm{R}=4\mathrm{R}$$$$\frac{1}{{\mathrm{R}}_{\mathrm{p}}}=\frac{1}{2\mathrm{R}}+\frac{1}{4\mathrm{R}}=\frac{3}{4\mathrm{R}}$$$${\mathrm{R}}_{\mathrm{p}}=\frac{4\mathrm{R}}{3}$$$${\mathrm{R}}_{\mathrm{total}}=\mathrm{R}+\frac{4\mathrm{R}}{3}=\frac{7\mathrm{R}}{3}$$$${\mathrm{I}}_{\mathrm{total}}=\frac{\mathrm{E}}{\frac{7\mathrm{R}}{3}}=\frac{3\mathrm{E}}{7\mathrm{R}}$$$${\mathrm{I}}_{\mathrm{t}}={\mathrm{I}}_{\mathrm{p}}=\frac{3\mathrm{E}}{7\mathrm{R}}$$$${\mathrm{V}}_{\mathrm{paralel}}={\mathrm{I}}_{\mathrm{p}}\times {\mathrm{R}}_{\mathrm{p}}=\frac{3\mathrm{E}}{7\mathrm{R}}\times \frac{4\mathrm{R}}{3}=\frac{4\mathrm{E}}{7}$$$${\mathrm{V}}_{2\mathrm{R}}=\frac{4\mathrm{E}}{3}\to {\mathrm{I}}_{2\mathrm{R}}=\frac{\frac{4\mathrm{E}}{3}}{2\mathrm{R}}$$$$=\frac{4\mathrm{E}}{6\mathrm{R}}=\frac{2\mathrm{E}}{3\mathrm{R}}//$$$$$$$$\mathrm{o}$$

Answered by DELETED last updated on 23/Aug/21

$$58).$$$$\mathrm{Q}=\mathrm{m}.\mathrm{c}.\mathrm{\Delta }\mathrm{T}=4000\times 4,2\times 22$$$$=400\times 42\times 22\mathrm{joule}.....\left(1\right)$$$$\mathrm{W}={\mathrm{i}}^2.\mathrm{R}.\mathrm{t}={\left(\frac{\mathrm{V}}{\mathrm{R}}\right)}^2.\mathrm{R}.\mathrm{t}$$$$=\frac{{\mathrm{V}}^2\times \mathrm{t}}{\mathrm{R}}=\frac{{220}^2\times \mathrm{t}}{55}.....\left(2\right)$$$$\left(1\right)=\left(2\right)$$$$400\times 42\times 22=\frac{220\times 220\times \mathrm{t}}{55}$$$$\mathrm{t}=\frac{400\times 42\times 22\times 55}{220\times 220}$$$$=\frac{4\times 42\times 5\times 11}{2\times 11}$$$$=420\mathrm{detik}=\frac{420}{60}=7\mathrm{menit}$$

Answered by DELETED last updated on 23/Aug/21

$$60).\mathrm{P}={\mathrm{i}}^2.\mathrm{R}$$$${\mathrm{i}}^2=\frac{\mathrm{P}}{\mathrm{R}}=\frac{12\times {10}^6}{40}=300.000$$$$\mathrm{i}=100\sqrt{30}\mathrm{A}$$$$\mathrm{V}=\mathrm{i}.\mathrm{R}=100\sqrt{30}\times 40$$$$=4000\sqrt{3}\mathrm{volt}$$

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