Question Number 151876 by tabata last updated on 23/Aug/21
Answered by Olaf_Thorendsen last updated on 23/Aug/21
$$\mathrm{A}\:=\:\mathrm{0}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{5}}{\mathrm{7}}+... \\ $$$$\mathrm{A}\:=\:\frac{\mathrm{0}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{2}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{6}}+\frac{\mathrm{5}}{\mathrm{7}}+... \\ $$$$\mathrm{A}\:=\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{n}}{{n}+\mathrm{2}}\:\:\:\mathrm{diverges} \\ $$