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Question Number 152001 by otchereabdullai@gmail.com last updated on 25/Aug/21

$$\mathrm{Four}\mathrm{members}\mathrm{of}\mathrm{a}{\mathrm{school}}^{\prime }\mathrm{s}\mathrm{first}\mathrm{eleven}$$$$\mathrm{criket}\mathrm{team}\mathrm{are}\mathrm{also}\mathrm{in}\mathrm{the}\mathrm{first}\mathrm{fourteen}$$$$\mathrm{rugby}\mathrm{team}.\mathrm{How}\mathrm{many}\mathrm{members}\mathrm{play}$$$$\mathrm{for}\mathrm{at}\mathrm{least}\mathrm{one}\mathrm{of}\mathrm{the}\mathrm{two}\mathrm{teams}$$

Answered by mr W last updated on 25/Aug/21

$$onlyplayingcriket:11-4=7$$$$onlyplayingrugby:14-4=10$$$$playingboth:4$$$$----------$$$$sum:21$$$$i.e.21membersplayatleastinone$$$$team.$$

Commented by otchereabdullai@gmail.com last updated on 25/Aug/21

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{prof}!$$

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